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this is the second video in static
indeterminacy. Here we will learn about
finding the static indeterminacy of pins
with different end conditions.
Before solving these questions we will
know how to find the static
indeterminacy of beams 
when one end is fixed and another is
pinned or when put the insert pinned.
let's begin for both end hinged.
for hinge, support reaction is given
 
for hinge support reactions are given
like this one in horizontal direction
and one in vertical direction. So we
will have
total four unknowns. Static equilibrium
equations equal to three.
So static indeterminacy equals to 4
minus 3 equals 1
this is how we get one static
indeterminacy for hinge at both ends.
There is no internal indeterminacy. This
static indeterminacy is external
indeterminacy.
Now let's see for one hinged and another
fixed end. let's draw the support reactions
 
 
 
these are the support reactions in X
Direction y direction and moment at the fixed ends. Unknowns equals to
2 at hinged
and three at fixed end
equals to five. Static equilibrium
equations equals to three. Summation
FX, Summation FY, summation moment
equals to 0. These are the static
equilibrium equations
now static indeterminacy equals to 5
minus 3 equals to 2. so for one intensed
and another end fixed, we have a static
indeterminacy equals 2.
Both ends both fixed, three static
indeterminacy
both end pinned, we get 1 static
indeterminacy.
one pinned and another fixed we get two
static indeterminacy. This is illustrated
in the table.
Using this we will find the static
indeterminacy of frames
Using the conditions we have found, we
will be solving this frame and this
frame in the next video.
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