All right guys, so for this trick the
spectator will need to choose a card,
not physically but mentally choose a
card.
So they can just choose any card in the
deck.
So since we do not have a spectator, let's
just choose a random card let's say
the jack of hearts. So we lose the jack of
hearts in the middle of the deck.
It's somewhere in the middle, now the
spectator can go ahead and cut the
deck as many times as he wants.
So let's say they cut it two or three
times
until they're fully satisfied and the
selection was the
jack of hearts.
So now that they have the jack of hearts
I'll tell them that I can as a magician
memorise the whole deck.
To memorise the whole deck is not an easy job,
it requires a lot of dedication.
so the jack of hearts
let's say will be around the eighth card
from the bottom of the deck. So
8 cards from the bottom, one, two,
three, four, five, six,
seven, eight, the jack of hearts.
So that is the trick guys.
Hope you liked it, so stick around for
the tutorial.
All right guys so for this tutorial you
need to know what is the Si Stebbins
stack.
If you don't know what a Si
Stebbins stack is you can check out the
tutorial on the channel.
So now that you know what the Si Stebbins stack is
you can do this trick, it requires no
sleight of hand, only a bit of mathematics
and there is a formula which i will give
you in the video.
So the trick is as follows:
the spectator mentally selects the card
so no need to physically take the card
out
and then place it place it back in the
deck.
They just think of a card so let's say
for the tutorial let's
just use the ace of spades and they can
cut the deck, as you know
cutting the deck won't change the order
of the Si Stebbins stack, only single
cuts. The selection is the ace of spades. What
you need to be
looking for is at the four bottom cards.
So the four bottom cards consist of all
four suits because
of the order of the Si Stebbins stack
and you need to look for the pair of
their chosen card. So their chosen card
is the ace of spades
and the pair is going to be a spade. So
spade here
is the seven of spades.
The formula is as follows:
you take the pair, the bottom pair,
that is the same suit as their selection,
and you need to subtract it with the
with their selection the value so it's
seven minus one,
ace is one, jack eleven, queen twelve
and king thirteen. So seven minus one is
six.
Then we need to multiply by four,
so it was six times four is twenty four
and then you need to remove the offset,
subtract the offset. The offset in this
case is 0 because
it is the number of cards below the pair.
So if the pair was the jack of
diamonds so if their selection was a
diamond
the offset would have been three because
there are three cards
below this, if it was a club that would
be
two cards and if it was a heart if there
would be only one card.
So in this case for the spade there is
no
card below this, so the offset is zero. So
I'll just put
the formula here so that you can
remember it.
Now once you have it here, so it was
24 cards now it will be from the top.
So you count 24 from the top. 1, 2, 3, 4, 5, 6, 7, 8,
9, 10, 11, 12, 13, 14, 15, 16, 17,
18, 19, 20, 21, 22, 23 and the 24th
card
is going to be their selection.
Trick I, the performance of the trick I
dealt from the bottom.
Now this was different because the
selection was
greater than the bottom card. So let's say
the selection was just the two of hearts.
So the two of hearts will be this pair,
you subtract it from the two, so 1 minus
2 is going to be...
So you need to add 13 to this one. So
it's 14 and then you subtract 2, it's 12
and then the normal formula times 4, 48
minus 1.
It's 47. So 47 is
a bit too much from above, so
i just counted from the bottom. It's
going to be
just four after this.
So this is second then it will be just
four cards after this
there will be the two of hearts. It's
going to be
four because there are only
three suits (before the) between the
two hearts and it's going to be like
this,
another three and then the three,
another three and then the four, it goes
on like this.
If the two cards are near
the value it's one and then you need to
find the two or the three
and then you can just
count from the bottom there. The spectator
will not know what you're doing so they
don't really know
that you have to count from the top.
If you're not confident enough to do it
from the bottom you can just
apply the formula and deal from the top
but sometimes
it's going to be too much to deal from
the top
and waste some some time but it's up to
you.
So that's it guys about this tutorial,
it's a very easy trick with no
sleight of hand, only some maths.
