In this illustration, we'll analyze the tension
in a supporting cord. here we are given that
the figure shows a solid block of volume thousand
centimeter cube and density point 8 gram,
per centimeter cube submerged in a liquid
of density 1 point 2 gram per centimeter cube
and tied to bottom with a cord. here it is
saying if container is accelerating up at
5 meter per second square then we are required
to find the tension in this cord. so in this
situation first we can draw the free body
diagram of this block. on which in downward
direction the force will be tension plus.
m g effective. where we can write the value
of g effective is equal to g plus ay as the
container is accelerating up with acceleration
ay, so, here we can write the value of g,
is 10 meter per second square and, if we take
the acceleration which is given as 5 so it'll
be, 15 meter per second square. and in upward
direction the block will be experiencing the
buoyancy force. so here we can write for,
equilibrium of block, in frame of, container.
here we use, in this situation buoyant force
is equal to t plus. m g effective. say, here
the value of tension, will be getting is buoyant
force, minus m g effective. here if we substitute
the values the buoyant force can be given
as v ro g. here we can solve it in c g s unit
as volume, of block is given as thousand centimeter
cube. so buoyant force we can write as v ro
g minus m g effective. and here the volume
is thousand. multiplied by the density of
liquid we are given with 1 point 2 gram per
centimeter cube. this 1 point 2. and the value
of, g here, we can again take as g effective
only because, with respect to container the
buoyant force will be acting with respect
to effective gravity, so effective gravity
here we can take as 15 hundred. minus the
mass of block, we can substitute as the volume
multiplied by its density so this is thousand,
multiplied by zero point 8 multiplied by,
15 hundred. so numerically when we simplify.
this will give us 6 into 10 to power 5. dyne,
the force acting on it and, we convert it
an s i unit this will be 6 newton. that is
the result of this problem.
