This is Dr. B.
We're going to draw the Lewis structure for
I2, Iodine gas, a very pretty purple gas.
So let's start out.
Iodine is in group 7 of the periodic table.
That means it has 7 valence electrons, so
we have 7.
But we have two Iodine atoms, so we need to
multiply that by two, giving us a total of
14 valence electrons.
So we're going to spread those 14 valence
electrons around the two Iodine atoms, form
a chemical bond, and fulfill the octets so
that each Iodine has eight valence electrons.
So let's draw an I here, and let's put this
and make sure they look like I's.
OK.
So we'll start first by putting two between
them to form the chemical bond.
So we've used 2, 4, 6, 8, 10, 12, 14, which
is how many we have to work with; and let's
see if we have octets.
This Iodine has 2, 4, 6, 8; and this Iodine
also has 8.
We use a total of 2, 4, 6, 8, 10, 12, 14,
which is how many we had to start out with.
That's the Lewis structure for Iodine.
We could also draw it, if we wanted to, as
a structural formula, and that would look
like this right here where these two bonding
electrons are represented by this single line
right here.
So that line means two valence bonding electrons.
This is Dr. B., and thanks for watching.
