, I want to differentiate really
complicated functions. As a concrete
example take a look at the function f of x
equals 1 plus 2x to the fifth power. Let's
try to differentiate this function. We
could approach this in a couple different
ways. First of all, I could just expand it
out. Alright. So I'm just going to expand
this out 1 to the fifth is just one, plus
ten x, plus 40 x squared, plus 80 x cubed,
plus 80 x to the fourth, plus 32 x to the
5th. Now, it's just a polynomial so I can
fearlessly differentiate it. So, f prime
of x, by differentiate this, the
derivative of one is zero, the derivative
of ten x is ten, the derivative of 40 x
squared is 80 x, and 240 x squared, 320 x
cubed, and 160 x to the fourth. Of course,
if we're clever at this point, we can also
see that this mess factors. So it's sort
of believable as a factor of ten here,
since all of these coefficients end in a
zero. This is ten times one plus eight x
plus 24 x squared plus 32 x cubed plus 16
x to the fourth. What's way less obvious,
I mean not obvious at all, is that this
mess also factors. It happens to be one
plus two x to the fourth power. This is
not an accident. What if we instead
applied the change rule to original
problem? So let's compute the derivative
to the change rule. The first step is
we're going to split up the function f
into a composition of two functions, g and
h, g here, the outside function is the
fifth power function, and h, the inside
function is one plus two x. So if I
combine those two functions, save the
composition, I get back f. Now, I want to
differentiate f and, by the chain rule,
that's the derivative of the outside, add
the inside function, times the derivative
of the inside function. In this case, what
is the derivative of the outside function?
The derivative of g is five x to the
fourth. So I'm going to take that but if
evaluate it at h. five h of x to the
fourth multiply by the derivative of h.
What is the derivative of h? Well, it's
two. Well, look what I got here. I've got
five, h of x is one plus two x to the
fourth times two, that's ten times one
plus two x to the fourth, that's exactly
what we calculated before. It's really
nice example, because it shows that we're
doing the same calculation. We're
calculating derivative of the function one
plus two x to the fifth power, but we're
doing it in two different ways,
nevertheless, we get the same answer.
Somehow, mathematics is conspiring to be
consistent. Okay, well, let's try another
example. Well, here's a more complicated
function, f of x equals the square root of
x squared plus 0.0001. What's the
derivative of f? We can't simply expand
this function out, and in fact, if you
graph the function, you might think that
the function is not differential, because
the graph of the function has this sharp
corner at the origin, but let's zoom in
and see what this actually looks like if
we zoom in close enough. If we zoom in
close enough, the thing doesn't look like
it has a sharp corner anymore. It actually
looks like it's curved and if we zoom in
any further, the thing would look more and
more like a straight line. What we're
really seeing is the function is
differentiable. Now, we can verify this
algebraically, we can use our derivative
laws, like a change rule, to actually
calculate the derivative of this function.
We'll differentiate this by using the
change rule since this is really a
composition of two functions. This is a
composition of the square root function
and this polynomial, x squared plus
0.0001. Alright, so the derivative of f is
the derivative of the outside function,
which is the derivative of the square
root, which is 1 over 2 square root And
it's the derivative of the outside
function evaluated at the inside, which is
x squared plus 0.0001. I have to multiply
by the derivative of the inside function.
What is the derivative of x squared plus
0.0001? Well, that's the derivative of the
x squared, since it's a constant and the
derivative of x squared is two x. So the
dirivitave of f is one over two t imes the
square root of x squared plus 0.0001 times
two x. I could make that a little bit
nicer looking. I could cancel these twos
and write this as x over the square root
of x squared plus 0.0001. What happens at
zero? So let compute the derivative at
zero. Well, if I plug in zero for x, I've
got zero over zero squared plus 0.0001.
The denominator is not zero, the numerator
is zero, the derivative at zero is zero
and you can see that from the graph. If I
look at when x equals zero, the tangent
line at that point is horizontal, the
slope of that tangent line is zero. The
derivative at zero is zero, and there's
more awesome things that you can see by
looking at the derivative. If you look at,
say, the limit of the derivative as x
approaches infinity, that's the limit of
this quantity, which is one, and the limit
of the derivative as x approaches minus
infinity is negative one and you can see
this visibly on the graph of the function.
If you plug in a really big number and
look at the tangent line there, that
tangent line has slope close to one. And,
if you plug in areally negative number and
look at the tangent line there, That
tangent line has slope close to minus one.
Our derivative rules are revealing facts
that are hidden. This function looks like
it's got a sharp corner, but we know, by
applying our differentiation rules, by
using the change rule, that this function
is in fact differentiable. And we know
that if we zoom in close enough, the thing
looks like a straight line, the derivative
rules really revealing this structure at
very small scales.
