Hi, Friends
In this video we are going to apply superposition Theorem to a simple problem, so let us take a problem
so here
We have taken a problem where?
Sources are more, but only one resistance is present
So let us have the value to these sources
So this voltage source is of six volt
this current source
5 Amp
voltage source of 10 volt and
only resistance present of 5 Ohm
We are supposed to find out
Voltage between points A and B. That is VAB
using superposition theorem
so let us start
First I will consider only one source acting alone, so I will consider six volt
acting alone
remaining sources that is 5 ampere of current source and
We have discussed current source we need to open circuit so 5 ampere is open circuited
and
10 volt another voltage source that
i will short circuit
Since modification is made to the original circuit. We need to redride
So I
will have
Six volt acting alone, so this will be present
Remember we are not touching resistance at all so that will also remain as it is
current source is open circuit and
Voltage source is short circuited
So I will get the circuit having only source
6 volt present and a resistance
5 ohm if you see properly
from this point a to
Point b. I am
having a voltage source connected which is 6 volt and
5 Ohm is across the 6 volt so I can say directly VAB
equal to
6 volt and VAB is a partial answer because I have considered only one source
So I will consider V'AB as a notation
So this will be your answer directly
let us go to the second step in the second step. I will consider second voltage source
that is 10 volt
so 10 volt acting alone
Six volt is a voltage source. We will short-circuit that so six volt is short-circuited
and
5 ampere is a current source
We need to open circuited
level of this there is modified circuit, so 6 volt is short-circuited
Once again, we are not touching
Resistance at all so that will be as it is
5 ampere
open circuited and
Only source acting this time is 10 volt
So I will get resultant circuit like this
again, I
Need to consider this loop
Which is covering a and B points?
So in this loop
Since it is open circuited here at point A as well as at point B current flowing through 5 Ohm resistance
will be
0 ampere  because it is not closed
so obviously whatever voltage source is present that will be the voltage across points A and
B so here also I can directly say
VAB double dash because it is only because of 10 volt acting alone
10 volt
Second answer I am getting third step let us consider 5 ampere acting alone
Now remaining sources are voltage sources. I need to short-circuit them so 6 volt and
10 volt are
short circuited
So the modified circuit diagram will look like this six volt is shorted
Resistance will remain as it is
only source acting is a current source of 5 ampere and
This 10 volt is also short-circuited
now in order to get
Voltage between these two points. I should know current flowing through the 5 ohm  resistance as well as
number of Elements coming in this loop
Here only 5 Ohm resistance will come into the picture so I should find out
What is a current flowing through 5 Ohm resistance?
You cannot say current flowing through the 5 ohm resistance is 5 ampere
because 5 Ohm resistance is actually short circuited because of this link so
actually speaking
You will get a loop like this from a it will bypass 5 Ohm resistance
And it will come back to this b. Point like this it is just a wire
bypassing 5 Ohm resistance so I can say
voltage of
Points a and B. Which I will denote as I triple dash VAb will be 0 volt now
You may be wondering what will happen to this 5 ampere current?
5 ampere current
Will flow through this part of the circuit
It will just circulate over here since I am not having any resistance in this part
Therefore there won't be any voltage drop despite of a current source present
it was just circulate in this loop, so
Ultimately, I will get V'AB or I should say V "'AB  at 0 volt
finally that as per the statement of superposition theorem the response here response is a voltage between
Points a and B. Will be the algebraic sum of
response because of First source
response because of second source and
response because of third source
Since in all the three answers, I am getting answer VAB. Where A is positive with respect to B
So I can simply add all the responses so six volt
Plus Ten volt
plus zero volt and
Finally VAB. I will get
16 volt and here. I can add one more line to complete answer I am
Getting this answer
when a  positive
With respect to B
so whenever voltage is asked you better write down this statement which point is positive with respect to which point and
In case of a current as a response we will Denote
Direction along with A
Magnitude so here we have seen a numerical having three sources present and only one resistance
But actually the answers are very simple it will be just a simple
Concepts that we have already learned in subsequent videos. We will solve more numericals based on superposition theorem
Thank you
