In this illustration, we'll analyze 3 liquids
in a u tube. we are given that a u tube contains
water and oil separated by mercury here we
can see this water this is oil. and this would
be the mercury. and the mercury columns in
the 2 arms of tube are at the same level with
10 centimeter of water in 1 arm and 12 point
5 centimeter of oil in the other. as shown
in figure, we are required to find the relative
density of oil. here, we can write, as. mercury
level. in the 2 arms. are equal. so we can
say pressure. must be equal. at the levels.
of mercury. in, both, arms. so, in this situation
here we can directly write pressure at point
ay must be equal to pressure at point b. so
at pressure at point ay is p atmospheric plus.
water length is 10 centimeter so we can write
it, zero point 1 multiplied by ro of water
multiplied by g. this must be equal to pressure
at b will be p atmospheric. plus the length
is zero point 1 2 5 multiplied by ro of oil
multiplied by, g. so in this situation p atmosphere
gets cancelled out and this will give us the
value of, ro oil. is equal to, or we can directly
calculate the value of ro oil in terms of
ro w and then the relative density this is.
10 divided by 12 point 5 multiplied by, ro
w. or the relative density of oil can be given
as ro oil by ro water. is equal to 4 by 5
that is zero point 8, its the result of this
problem.
