Hey, guys welcome to we civil engineers.
In this video, I’m going to teach you how
to calculate the quantity of cement, sand,
aggregates & water in M25 grade of concrete.
Let’s assume the volume of concrete as 1
cubic meter,
Hence the volume of wet concrete equals to
1 cubic meter.
we all knew that to get the dry volume of
concrete, we need to multiply wet volume with
the dry factor.
Therefore, Dry volume of concrete equals to
wet volume multiplied by 1.54
Here, 1.54 is the dry factor, also known as
the multiplication factor of concrete. Therefore,
Dry volume = 1 x 1.54 = 1.54.
Here 1 is wet volume of concrete
to calculation of cement quantity, you have
to remember a simple formula.
I.e., Quantity of cement = (Dry volume of
concrete x cement ratio)/(sum of the ratio).
Mix ratio of M25 grade of concrete is 1:1:2,
which means cement, sand & aggregates are
in the ratio of 1:1:2.
Now, We know the values of the dry volume of the
concrete & ratio of different material.
So, substitute these values in the above formula
to get the quantity of cement.
Therefore, Cement = (1.54 x 1)/(1+1+2)=0.385
m³.
Since cement is measured in term of weight,
we have to convert this volume into weight.
For that, just multiply the density of cement
with volume.
Weight of Cement = 1440 x 0.385 = 554.4 Kg
To get the number of bags, divide the weight
of cement with the weight of one bag.
If you divide 554.4 with 50 then you will get it as 11.088 No's.
which is approximately equals to 11 no's.
Since cement and sand are in the ratio of
1:1
The Quantity of sand is equaled to the quantity
of cement.
∴ Quantity of Sand = 0.385 x 1 = 0.385 m³
Sand is also measured in cubic foot and tonnes.
So, let’s convert cubic meter volume into
cft and tonnes.
∵ 1m³=35.3147 Cubic Feet (CFT). Multiply
cubic meter volume with 35.3147 to get the
volume in CFT.
Therefore, Quantity of sand in CFT= 0.385
x 35.3147 = 13.596 CFT
Now, multiply the density of sand with volume
to get the weight of sand in tonnes.
 Here, Density of Sand = 1600 kg/m^3
Weight of sand= 0.385 (Volume of sand in terms of cubic meter)
x 1600 (I.e.,density of sand)=  616 kg (0.616 tonnes)
Since cement and  coarse aggregates are in the ratio
of 1:2
The Quantity of coarse aggregates is equaled to the quantity of cement x 2
∴ Quantity of Coarse Aggregates = 0.385
x 2 = 0.77 m³
Quantity of Coarse Aggregates in
CFT= 0.77 x 35.3147 = 27.217 CFT.
For converting meter cube value into cubic foot we are multiplying 0.77 with 35.3147
Now multiply the density of coarse aggregates with volume to get the weight of coarse aggregates in tonnes.
Here, Density of Coarse Aggregates is 1520 kg/m^3
∴ Weight of Coarse Aggregates= 0.77 x 1520
=  1170.4 kg or (1.170 tonnes)
Assume water-cement ratio as 0.50
To get the quantity of water, we have to multiply
cement quantity with 0.50.
Therefore, Quantity of water = 554.4kg  (i.e., weight of cement) x 0.50 (i.e.,water-cement ratio)
= 277.2 kg or liters.
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