In this video we are going to see how to apply
series and parallel connection concepts of
resistors, in order to solve numerical.
Let us take a numerical to illustrate the
concept of series
and parallel connections of the resistor.
So here I have taken a numerical of  a random
connection of resistors either in series and
parallel.
Let us give value to them.
All the resistors
are in ohm, so I do not need to write for
individual resistor.
Now let us check how many
connections are there which are series or
parallel.
As far as our concept goes this 2 and 4 ohm
resistors in series, so its equivalent is
2 + 4 which is nothing but 6 Ohm, at the same
time if you
see properly this 3 ohm and 3 ohm are also
in series so I&#39;ll get this 3 + 3=6 Ohm.
So as soon as
I have made this connections and converted
into single resistor, let us redraw the circuit.5
ohm
is not touch.2 ohm,4ohm become a series combination
and therefore I will get 6 Ohm. 3 and 3
will also become 6 Ohm and 2 ohm remain untouch.it
is a  5 ohm,2 ohm,6 ohm and 6 ohm. if
you see properly between these 2 points,6
ohm and 6 ohm are connected.
a parallel
combination.
6 parallel 6.See whenever 2 resistors are
given in a parallel combination, you can
get a direct answer.
The answer will be multiplication of two values
divided by addition of two
values.so here, if i solve I&#39;ll get answer
3 ohm. so whenever two resistors are given
in parallel
you can use a direct formula.
Multiplication of two values divided by addition
of two values.
Hence I will get 3 ohm.so let us redraw the
circuit now,5 ohm untouch,6 ohm -6 ohm becomes
3
ohm,2 ohm untouch.If I solve further  I&#39;ll
come to know this 3 ohm and 2 ohm are in series
which
will give you a 5 ohm and after redrawing
the circuit, circuit will look like this.
from the circuit it is
obvious that this 5 ohm and this 5 ohm connected
between these two same points.
I can say 5
and 5 are in parallel and since two resistors
are in given parallel combination, I can say
the
equivalent is multiplication of 2 divided
by addition of 2 and if it&#39;s all you will
get answer 2.5 ohm.
so for the circuit I can say the entire original
circuit having so many resistors can be reduced
into a single resistor.
between points A &amp; B, which I named as
RAB, the value is 2.5 ohm, so
here we have taken a basic example where so
many series and parallel combinations are
applicable.
Here in subsequent videos we will see more
numerical like this.
thank you.
