Hi friends in this video we are going to
solve a problem based on EMF equation of
a single phase transformer so statement
of problem is like this a 50 KVA 2200 /
440 volt 50 Hertz single phase
transformer has primary turns of 200
determine first flux in core second
secondary turns third rated primary
current and fourth rated secondary current
so it's a simple problem based on
equation of EMF in a single phase
transformer so lets solve it lets
list all the things given so here they
have given a rating over transformer
it's a 50 kVA and voltage ratio is given
what else they are given primary turns
which are 200 so number of turns primary
side N1 equal to 200 so how we are going
to use this given things in order to
calculate these things flux secondary
turns the rated primary current and
secondary rated current so first of all
I will write EMF equation of a
transformer
so it is E1 equal to 4.44 Phi M
into F into N 1 certain things are given
over here this is nothing but a e1 a
primary side induced EMF Phi M it is a
maximum flux inside a core that we are
supposed to calculate frequency is 50
years given and number of primary turns
are 200 so if we solve this you will get
Phi m equal to 2200 divided by 4.44
 multiplied by 50 multiplied by 200 if
you saw using a calculator you will get
maximum flux in the core equal to 0.0495
 Weber lets
find out secondary turns now we know EMF
ratios even upon e2 is nothing but N 1
upon n 2 so e1 is given 2200 E2 is 440
number of primary turns are 200 so we
can calculate number of secondary turns
n 2 by solving this equation so n2 equal
to 200 multiplied by 440 divided by 2200
so if we solve you will get n 2 equal to
40 so 40 turns you will get at the
secondary side lets calculate rated
primary current
so rated primary current is nothing but
I1FL is also called as a full load
current so if I multiply this with
primary side voltage I will get
volt-ampere of a transformer so V 1 is
approximately same as e 1 if we
neglecting a primary side resistance and
leakage reactance so what I can say e 1
I 1 FL equal to transformer VA so e1 is
2200 I 1 FL you are supposed to
calculate and transformer VA is given
as 50 50 kVA so I can write here it
50,000 KVA now from this I can get I 1 FL
which is equal to 50,000 divided by 2200
after solving this you will get primary
side rated current nothing but a full
load current equal to 22.7273
ampere and we can
observe that KVA rating of a
transformer from the primary side as
well as secondary side is same how we
are going to use this concept now we can
say E 2 into I 2FL is nothing but VA of
a transformer E 2 is 440 I 2FL we are
supposed to calculate and VA rating of a
transformer is 50000 from this I
can get rated secondary current equal to
50000 divided by 440 solution of
this equation will give you I 2FL equal
to 113.6364
ampere this is the required answer
so here we have come to an end of
problem based on EMF equation of a
single phase transformer thank you
