Solve two x squared
plus eight x plus three equal to zero.
As you see, it is a standard
form of quadratic equation
to determine the value of a, b, c.
a is two, b is equal to
eight, c equal to three.
Now using quadratic formula,
x equal to negative b plus minus
the square root b squared
minus four ac over two a.
Now, substituting the value
of a, b, c in this situation,
you get x equal to
negative eight plus minus
the square root eight squared
minus four times two times three
over two times two.
Then we get x equal to
negative eight plus minus
the square root, eight squared is 64,
minus, four times two times three is 24.
Over two times two, four.
Now x equal to negative eight plus minus
the square root, 64 minus 24 is 40,
over four.
Then, we can write x equal
to negative eight plus minus
the square root of 40 is two
times square root 10 over four.
Now, as you see, there's two as a common,
so take two as common outside
and you get negative four
plus minus the square root 10 over four.
As you see, two divided
four is one over two,
so you get x equal to negative four
plus minus the square root 10 over two.
Now you can separate that in two parts,
so x is equal to negative four
plus the square root 10 over two
or x equal to negative four
minus the square root 10 over two.
And this is our final answer.
