This is the C4H10 Lewis structure: Butane.
For Butane, we have a total of 26 valence
electrons.
Whenever we see the ending, "ane", we know
that we're going to have Carbons and Hydrogens
single bonded.
That makes it a little bit easier to draw
the C4H10 Lewis structure.
We'll put four Carbons in a row and then we'll
put Hydrogens around them.
Because each Carbon needs to have four single
bonds--each bond having two valence electrons,
that'll give it an octet--we'll have three
Hydrogens on the end Carbons and two on the
center, like this.
There are the three on the ends, and then
we'll put two Hydrogens on the central Carbons.
Next we'll place a single bond between each
of the atoms to show that a pair of electrons
is being shared.
So we've used all 26 valence electrons for
the C4H10 Lewis structure, and we can see
that each Carbon has four single bonds.
Since each single bond has two valence electrons,
that means that each Carbon has an octet.
Each Hydrogen has a single bond, so it has
two valence electrons.
That means that it has a full outer shell
as well.
So we've used all the valence electrons that
we had for C4H10 and everything has an octet.
So we're done with the Lewis structure for
C4H10, Butane.
This is Dr. B., and thanks for watching.
