Hello this is problem number 4
in the Exam 2 Review and
it has ugly big numbers. I don't think I like that.
Our a-number is going to be 10,
our b-number is going to be 39
and our c-number is 27.
I'm going to use the quadratic formula.
Ignore the fact that the variable is "a", and 
think of it as "x".
Teacher writes quadratic formula.
Teacher substitutes numbers in for a, b, and c 
in the formula.
OK
Teacher turns on calculator.
Uses calculator to calculate the number 
under the radical.
its 2601
-39
plus or minus the square root
of 2601
over 20.   Teacher tests to see if 2601 is a 
perfect square.
The square root of 2601 is 51.
The first solution will be
(-39-51)/20
 -9/2
The second solution will be
(-39+51)/20
nine plus
Which equals
12 over 20 and reduces to
3/5.
Teacher enters solution set into MyMathLab.
,
Calculated solutions are correct.
