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previous lecture we have studied what is
Faradys law and based on that we have
studied finest first law and second law
and we have also formulated a formula
where we could estimate what would be
the weight of the modulus of since they
put deposit when this much or a
particular amount of current is fast in
the solution at a particular time so now
let us know the numerical based on that
equation
so ever mention question relates the
fairness first law and felt a second
road in which what we have to calculate
is we have to calculate the mass of the
copper metal produced during the age of
5 ampere of current through the copper
sulphate solution 400 mint the molar
mass of copper was found to be sixty
three point five gram per moon so in
this case the first thing that we should
do is we should extract the data from
the given cushion and the given cushion
says and we have a data when 5 ampere of
thread is first so that for current is
related by I therefore I is goes to Phi
appear the next is they have mentioned
fine and in this case the time is 100
minute
so whenever the time is been mentioned
so the first thing that you should do is
you should convert it into seconds so
what I'm going to do is hundred into 60
seconds so this will be giving me an
inset like six thousand second and the
next thing which is much more important
that is molar mass of copper is to be
provided to us
so therefore molar mass of copper and I
see you they have provided us as sixty
three point five gram per mole and the
formula that we have is the common
formula that is w equals to Z I e
divided by 96500 so this is the formula
that we have got and we have to estimate
the mass that we have to estimate the
weight on the copper that is being
deposited so the value of i0 dose the
value of P is known to us but this value
of Z that is equivalent weight is not
known to us so how can we calculate this
thing so let us see enough
so that let me tell you the Z which
means equivalent weight is nothing but
modular weight divided by valency of the
metal in ionic form so the solution that
is been provided to us is copper
sulphate solution so when you dissociate
or when the dissociation of copper
sulphate occurs it is converted into Cu
2 plus plus so4 2 minus so because of
which the molecular weight that is been
given to us as sixty three point five
but the valency of the metal in I deform
here you can see the oxidation number as
two so because of help of this we could
estimate the value of Z that is
equivalent bit
so therefore the moniker weight which is
given as sixty three point five divided
by the valency of metal in ionic form in
this case is two plus one divided by two
so therefore the answer that I could get
is thirty one point seven five so this
is the value of equivalent weight that
we have got and again it is molecular
weight the molecule it is has an unit of
gram per mole so similarly the
equivalent weight of Z will also be gram
per mole and since it is divided by the
valency so well you see is just a number
so we have got the value of Z and now we
have can easily calculate what will be
the value of W that is the venue of
weight
so therefore W is to Z I T divided by
nine six five zero zero in this case the
value of Z that is the value of
equivalent weight that we have got is
thirty-one point seven five and then
that of the current that they have
provided to us was five appear and the
time that we have been calculated and it
was provided in in minutes but we have
converted into seconds which was found
to be six thousand BR by nine six five
zero zero so this means the answer that
we could get is
nine point eight seven zero but the unit
of the weight in this case will be great
because this kind of experiment is being
done and the unit that is being taken
that we have taken the unit of time
which was present minute we have taken
the time in seconds and we have taken
the molecule rate in gram per mole so
therefore the answer that we have got
now will be in the unit of again so this
is how we have calculated the weight of
a particular substance and in this case
of a particular copper when present in
the copper sulphate solution and
electrolysis has happened so how many
amount of copper has been deposited on a
particular electrode so this was very
much easy which was based on Faraday's
first one so thank you friends for
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